Question

Find the least 3 digit number which when divided by 20, 30, 40 and 50 leaves a remainder 10 in each case
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Answer 1

Hey!!Mate

Here is your ans:-

Step-by-step explanation:

Find the least three digit number which when divided by 20, 30, 40 and 50 leaves remainder 10 in each case. ∴ Required number = 600 + 10 = 610. Hence, the least three digit number which when divided by 20, 30, 40 and 50 leaves remainder 10 in each case is 610.

I hopes its help❤️❤️

Answer 2

Answer:

610

Step-by-step explanation:

Let us first factorize the given numbers as shown below:

20=1×2×2×5=2

2

×5

1

30=1×2×3×5=2

1

×3

1

×5

1

40=1×2×2×2×5=2

3

×5

1

50=1×2×5×5=2

1

×5

2

LCM of 20,30,40 and 50=2

3

×3

1

×5

2

=600

Therefore, the required number is 600+10=610.

Hence, the least three-digit number which when divided by 20,30,40 and 50 leaves remainder 10 in each case is 610.

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