Find the least 5 digit number which is exactly divisible by 20 25 and 30 for class sixth standard
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Answered by
0
Answer:
30000
Step-by-step explanation:
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Answered by
0
Answer:
10200,
Step-by-step explanation:
To find the least 5 digit number which is exactly divisible by 20, 25 and 30, we have to find the LCM of 20, 25 and 30
20 = 2*2*5
25 = 5*5
30 = 2*3*5
LCM = 2*2*3*5*5
= 300
So, LCM of 20, 25 and 30 is 300. But we need the least 5 digit number, which is exactly divisible by 20, 25 and 30.
Least 5 digit number = 10000.
10000 = (33*300) + 100
Next higher quotient is 34.
So, the required number = 34*300
= 10200
Hence, the required number is 10200, which is exactly divisible by 20, 35 and 30
Answer.
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