Math, asked by srijansrivastava28, 1 year ago

find the least 5 digit number which leave remainder 3 in each case when divided by 5 10 12 15 18 25 30 ​

Answers

Answered by kartik2507
2

Answer:

10803

Step-by-step explanation:

we need to find the LCM of 5 10 12 15 18 25 30

LCM is 900

least 5 digits number divisible by 900 is 10800

10803 is the number when divided by 5 10 12 15 18 25 30 leaves remainder 3

10803 = (5 × 2160) + 3

10803 = (10 × 1080) + 3

10803 = (12 × 900) + 3

10803 = (15 × 720) + 3

10803 = (18 × 600) + 3

10803 = (25 × 432) + 3

10803 = (30 × 360) + 3

hope you get your answer

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