Question

find the least 5 digit number which leaves reamainder 3 in each case ​

Answer 1

Answer:

99999-66666666666666

Answer 2

Answer:

first we need to find least common multiple (LCM) of 5, 10, 12, 15, 18, 25 and 30.

we can solve as l.c.m (5, 10, 15, 25,30) = 150 and l.c.m (12, 18) = 36, now to find l.c.m( 5, 10, 15, 12, 18, 25, 30 ) = l.c.m (150, 36) = 900. so any number which gives us remainder 3 must be in the form of N= 900 k+3 for some k integer.

so k= 1, N= 903 which is three digit number.

for k=2, N=1803 which is four digit number.

continuing in this manner we have

for k= 11, N= 9903 which is four digit number.

for k=12, N= 10803 which is five digit number.

so the least five digit number which gives remainder 3 when divided by 5, 10, 12, 15, 18, 25 and 30 is 10803.