Question

find the least 5-digit number which leaves remainder in 3 each case when divided by5, 10,12,15,18 and30

which solution​

Answer 1

Answer:

first we have to take LCM of 5,10,12,15,18&30 that is 180

Step-by-step explanation:

so find multiple of 180 till u get 5 digit number that is 10080 is smallest 5 digit no which is exactly divisible by 5,10,12,15,18&30 so after dividing 10080 by these we get 0 as remainder BT we need 3 as remainder so add 3 to 10080

so answer is 10083

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Answer 2

Answer:

Here is least meaning = Smallest

The smallest 5 digits number =10,000

Now we will plus =30+18+15+12+10+5=90+10,000=10,009

Then divide by 18 =10,009 ➗ 18 = 556¹