Question

find the least 6 digit number which is exactly divisible by 15 and 6 and leaves the remainder of 2 in each case​

Answer 1

The smallest six digit number is

100000

, the LCM of 15 and 6 is 30. <br> The smallest six digit number exactly divisible by 30 is

100020

. <br>

The required number is

10020+2=100022

.

Answer 2

Answer:

The answer is 32

as 6/32

= 6*5=30

=30-32=2 remainder

as 15/32

=15*2=30

30-32=2 REMAINDER