Question

Find the least count of a serew guage whose head scale is divided into 200 divisions, if it moves 5mm distance
when the head is rotated through 5 revolutions
WITH FORMULA
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Answer 1

Answer:

20

mass upon velocity

Explanation:

i hope it will help you

Answer 2

Answer:

here u go

Explanation:

pitch of a screw gauge = distance moved/no.of complete revolutions

                                      = 5/5

                                      = 1mm

L.C = pitch/no.of divisions

      = 5/40

      = 0.025