Question

Find the least multiple of 13 which when divided by 5,8 and 12 leaves the same remainder 2 in each case​

Answer 1

Step-by-step explanation:

The least multiple of 13, which on dividing by 4, 5, 6, 7 and 8 leaves remainder 2 in each case is : - GKToday. LCM of 4, 5, 6, 7 and 8 = 840. Let require number be 840 K + 2 which is multiple of 13. 3 + 2 = 2520 + 2 = 2522.

Answer 2

Answer:

962

Step-by-step explanation:

The least multiple of 13 should be some common multiple of [5,8,12] +2.

LCM OF 5,8,12 =480, BUT 480 +2 =482 is not a multiple of 13.

We multiple 480 by 2 =960 such that 960 is still some common multiple of 5,8 and 12

And 960+2=962 is divisible by 13 ie, a multiple of 13. such that when 962 divided by 5,8,12 leaves remainder 2..