find the least multiple of 7 which leaves a remainder of 4 when divided by 6 ,9 ,15 ,18.
Answers
Answered by
7
Step-by-step explanation:
L.C.M. of 6, 9, 15 and 18 is 90
Let required number be 90k + 4, which is multiple of 7
Least value of k for which (90k + 4) is divisible by 7 is k = 4
∴ Required number = (90 x 4) + 4 = 364
Similar questions