Question

Find the least natural number which when divided by 25 40 and 60 leave the remainder in each case 8

Answer 1

Answer:

608

Step-by-step explanation:

LCM of 25, 40 & 60 = 2*2*2*5*5*3 = 8*25*3 = 200*3 = 600. 600 perfectly divides the 3 numbers and leaves the remainder as 0. So, 600+8 = 608 is the smallest number which leaves remainder 8 when divided by 20, 40 & 60.

Answer 2

Answer:

608 is the Answer By Taking LCM of 25 40 and 60