Question

Find the least natural number which when divided by 25 40 60 leaves a remainder 8 ​

Answer 1

Answer:

608

Step-by-step explanation:

The Least Number which when divided by 25,40, and 60 leaves a remainder 8 is ((L.C.M of 25,40,and 60) + (8))

First, WE have to find L.C.M of the given numbers, For that purpose let us find prime factorization of the numbers :

25 = 5*5

40 = 2*2*2*5

60 = 2*2*3*5

Now, L.C.M  = 2*2*2*3*5*5 = 600

Now, to get the answer as explained above add 8 to 600, which is 608

Therefore the answer to your question is 608.

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