Question

Find the least natural number which when divided by 25, 40and60 leaves reminder 8​

Answer 1

Answer:

608

Step-by-step explanation:

The Least Number which when divided by 25,40, and 60 leaves a remainder 8 is ((L.C.M of 25,40,and 60) + (8))

First, WE have to find L.C.M of the given numbers, For that purpose let us find prime factorization of the numbers :

25 = 5*5

40 = 2*2*2*5

60 = 2*2*3*5

Now, L.C.M  = 2*2*2*3*5*5 = 600

Now, to get the answer as explained above add 8 to 600, which is 608

Therefore the answer to your question is 608.

Hope you understand it, Any query? Comment down.

Have a great day, Thanking you,

Bunti 360 !

Answer 2

We have to find the LCM of:

$\huge\boxed{\sf{25,40\:and\:60}}$

LCM of 25, 40 & 60:

$\implies$ 2 × 2 × 2 × 5 × 5 × 3

$\implies$ 8 × 25 × 3

$\implies$ 200 × 3

$\implies$ 600

Now:

600 perfectly divides these 3 numbers and leaves the remainder as 0.

So:

$\huge\boxed{\sf{600+8 = 608}}$

Therefore:

608 is the smallest number.