Question

find the least no to be multiplied by 9600 to make it a perfect square ​

Answer 1

Answer:

Step-by-step explanation:

sqrt(9600)

=9600

=24*4*100

=2*3*4*4*10*10

=2*3*2*2*2*2*2*5*2*5

=2^7*3*5^2

=so if we do sqrt of this number we get 5 outside the numbers that will be left over inside the root are 2 and 3

so multiplying one 2 and one 3 to the number inside the sqrt wwe get a perfect square

the leastr number to be multiplied is 6