Question

Find the least no which divided by 12,16,24and42leaves remainder 1

Answer 1

[ first of all we need to find the LCM of all the given numbers ]

LCM of 12, 16, 24 & 42
= 2×2×2×2×3×7
= 2⁴×21
= 336

♦ 336 + 1 = 337

♦ 337 is the number which when divided by all the given numbers leaves remainder 1


$hope \: this \: answer \: helps \: you \\ \\ thankyou$

Answer 2

Step-by-step explanation:

[ first of all we need to find the LCM of all the given numbers ]

LCM of 12, 16, 24 & 42

= 2×2×2×2×3×7

= 2⁴×21

= 336

♦ 336 + 1 = 337

♦ 337 is the number which when divided by all the given numbers leaves remainder 1.