Question

Find the least no which is divisible by all the numbers from 1 to 10

Answer 1

Step 1 : Find the prime factors of numbers from 1 to 10

1 = 1 × 1

2 = 2 × 1

3 = 3 × 1

4 = 2 × 2

5 = 5 × 1

6 = 2 × 3

7 = 7 × 1

8 = 2 × 2 × 2

9 = 3 × 3

10 = 5 × 2


Step 2 : Find their LCM

LCM of the nu.bers 1 to 10 = 1 × 2 × 2 × 2 × 3 × 3 × 5 × 7 = 2520



∴ least no which is divisible by all the numbers from 1 to 10 is $\boxed{\boxed{\textsf{2520}}}$



Additional information :-

LCM is the short form for "Least Common Multiple". The LCM of 2 numbers is smallest number that divide them evenly into. There are various methods to find LCM. For example, Prime Factorization method, Division method, etc.

Let's find LCM of two simple numbers like 2 and 3

First, find their prime factors

2 = 2 × 1

3 = 3 × 1

Second, Multiply all the numbers

2 × 1 × 3 × 1

= 6


∴ Their LCM is 6

Answer 2

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ANSWER

=>1 = 1

2 = 2 × 1

3 = 3 × 1

4 = 2 × 2

5 = 5 × 1

6 = 2 × 3

7 = 7 × 1

=>8 = 2 × 2 × 2

9 = 3 × 3

10 = 2 ×5

=》 So, LCM of these numbers = 1 × 2 × 2 × 2 × 3 × 3 × 5 × 7 = 2520

✔✔Hence, last updated number divisible by all the numbers from your search results for, and I will be reduced, since by all the numbers from 1 to 10 is 2520

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#Be brainly