find the least no which must be subtract of 980 to make it a perfact square
Answers
Answered by
1
980 - 19 =961
31^2 =961
So least no is 19
31^2 =961
So least no is 19
Answered by
2
on subtracting 19 from 980 we get 961 which is square of 31
and perfect square
therefore 19 is the required no.
and perfect square
therefore 19 is the required no.
Similar questions