. Find the least no which when divided by 15,27,35 and 42 leaves a remainder
Answers
Answered by
0
Answer:
15= 3×5
27=3×3×3
35=5×7
42=2×3×7
LCM=2×3^3×5×7=1890
Answered by
1
The least number which when divided by 15, 27, 35 and 42 leaves a remainder 7 in each case is 1897.
Similar questions