Math, asked by malhotrarekha77, 6 months ago

find the least no. which when divided by 35,56,91 leaves the same remainder 7 in each case​

Answers

Answered by kumarsantosh04984
1

Answer:

5(b). Forces of 20N, 30N, 40N, 50N are acting along positive X axis, positive Yaxis negative X axis and negative Y axis. Find resultant. .

Step-by-step explanation:

What is the net force? A. ON B. 40 N to the left HECANHEIRCOM C. 40 N to the right

Answered by ks5601536
1

Answer:

Ans. 3647

Step-by-step explanation:

The smallest number which when divided by 35,56 and 91

LCM = (35,56,91)

35= 5×7

56= 2^3×7

91 = 7×13

LCM = 8×5×7×13= 3640

The smallest number that when divided by 35,56,91 leaves a remainder 7 in each case

= 3640 + 7

= 3647

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