find the least no. which when divided by 6,15,18 leaves the remainder 5 in each case
Answers
Answered by
9
We will find the L.C.M of 6,15&18.
It would come to 90
Now according to the question ,
when 90 would be divided by 6,15&18 , it should leave a remainder 5.
Therefore we add 5 to 90 = 95
Cross check:-
95/6 Remainder = 5
95/15 Remainder = 5
95/18 Remainder =5
Thus the answer is right.
It would come to 90
Now according to the question ,
when 90 would be divided by 6,15&18 , it should leave a remainder 5.
Therefore we add 5 to 90 = 95
Cross check:-
95/6 Remainder = 5
95/15 Remainder = 5
95/18 Remainder =5
Thus the answer is right.
Answered by
0
ANSWER:-
LCM (6,15,18)
2×3×3×5. 3|6 15 18
=90. 2|2 5 6
5|1 5 3
3|1 1 3
1 1 1
ans:- 90 +5 = 95
Hope it's useful
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