Question

find the
least
nomber which when
Livided by
5,6, 8, 9
and 12
leaves a remainder
1
in each
Case but when divided by
13
leaves
no remainden
​

Answer 1

Answer:

FOR FINDING THE NUMBER WE SHOULD HAVE TO FIRST FIND L.C.M OF ALL :-

L.C.M Of 5,6,8,9,12 = 360

Now 360 × 1+ 1 = 361 which is not divisible by 13.

360 × 2 + 1 = 721 which is not divisible by 13.

360 × 3 + 1 = 1081 which is not divisible by 13.

360 × 4 + 1 = 1441 which is not divisible by 13.

360 × 5 + 1 = 1801 which is not divisible by 13.

360 × 6 + 1 = 2161 which is not divisible by 13.

360 × 7 + 1 = 2521 which is not divisible by 13.

360 × 8 + 1 = 2881 which is not divisible by 13.

360 × 9 + 1 = 3241 which is not divisible by 13.

360 × 10 + 1 = 3601, which is divisible by 13

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Therefore,RequiredNumber=3601.

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

L. c. m . = of 5,6,8,9,12 = 360

now...

360 × 1 +1 = 371

.........

so....

360×10+1 = 3601