find the least(non-zero) rationalising factor of 3 root 16 + 3 root 4 + 1 in simplified form.
Answers
Answered by
0
Step-by-step explanation:
(3 - \sqrt{5} ) \div (3 + \sqrt{5} )(3−
5
)÷(3+
5
)
on rationalising...
(3 - \sqrt{5} ) {}^{2} \div 3 {}^{2} - \sqrt{5} {}^{2}(3−
5
)
2
÷3
2
−
5
2
9 + 5 - 6 \sqrt{5} \div 9 - 59+5−6
5
÷9−5
14 - 6 \sqrt{5} \div 414−6
5
÷4
7 - 3 \sqrt{5} \div 27−3
5
÷2
on \: comparing \: with \: \: \: a \sqrt{5} - boncomparingwitha
5
−b
a = -3 and b = 7
Answered by
2
Answer:
a=+/-3 and b=7 this is the answer for the given question
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