Find the least numbe which when divided 40 50 and 60 leaves remainder 5
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1
Answer:
5
Step-by-step explanation:
- 40-5=35
- 50-5=45
- 60-5=55
- now the HCF of 35,45,55 is
- 35=5×7
- 45=3×3×5
- 55=5×11
- therefore, HCF of (35,45,55)=5
- the least number which when divided 40,50,60 is 5
- please mark me as a brainliest
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