Math, asked by 38907, 9 months ago

Find the least number by which 7938 should be divided to make it a perfect square? ​

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Answered by mysticd
8

 Resolving \: 7938 \: into \:prime \: factors , we \\get

2 | 7938

________

3 | 3969

________

3 | 1323

________

3 | 441

________

3 | 147

________

7 | 49

________

***** 7

 7938 = \red{2} \times \underline { \blue {3 \times 3 }} \times \underline { \blue {3 \times 3 }} \times \underline { \blue {7\times 7 }}

The prime factor '2' does not appear in a pair .

So, 7938 is not a perfect square .

Hence , the smallest number which is to be divided to make it a perfect square is '2' .

 \red{ Required \: perfect \: square } \\= \frac{7938}{2} \\= 3969 \\= \underline { \blue {3 \times 3 }} \times \underline { \blue {3 \times 3 }} \times \underline { \blue {7\times 7 }}\pink {  = 63^{2}}

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