Find the least number by which each of
the following numbers should be multiplied
to make 1488 a perfect cube Also find
the cube root of the product in each case.
Answers
Answered by
6
1) 5488
Explanation:
1 prime factorisation of 5488- 2*2*2*2*7*7*7
since factor7 is not forming pair 5488 must be multiplied by 7.
new number= 38416
prime factorisation- 2*2*2*2*7*7*7*7
square root=196
Answered by
0
Answer:
1) 5488
Step-by-step explanation:
1 prime factorisation of 5488- 2*2*2*2*7*7*7
since factor7 is not forming pair 5488 must be multiplied by 7.
new number= 38416
prime factorisation- 2*2*2*2*7*7*7*7
square root=196
mark as brainliest for the answer of part 2
Similar questions