Math, asked by ckpatel551, 8 months ago

Find the least number by which each of
the following numbers should be multiplied
to make 1488 a perfect cube Also find
the cube root of the product in each case.

Answers

Answered by BeStMaGiCiAn14
6

1) 5488

Explanation:

1 prime factorisation of 5488-  2*2*2*2*7*7*7

since factor7 is not forming pair 5488 must be multiplied by 7.

new number= 38416

prime factorisation- 2*2*2*2*7*7*7*7

square root=196

Answered by venkiprati
0

Answer:

1) 5488

Step-by-step explanation:

1 prime factorisation of 5488-  2*2*2*2*7*7*7

since factor7 is not forming pair 5488 must be multiplied by 7.

new number= 38416

prime factorisation- 2*2*2*2*7*7*7*7

square root=196

mark as brainliest for the answer of part 2

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