Question

Find the least number divided by 12,16,24&36 leves
Remender7 in each

Answer 1

Firstly we will find LCM of 12,16,24,36
12=2×2×3
16=2×2×2×2
24=2×2×2×3
36=2×2×3×3
LCM =2×2×2×2×3×3=144
Since 7 is the remainder on dividing by given nos. so the required least no is
144+7=151

Answer 2

First we have to find the L.C.M of 12,16,24,36

L.C.M by prime factorization method

12= 2*2*3

16=2*2*2*2

24= 2*2*2*3

36= 2*2*3*3

L.C.M= 2*2*2*2*3*3 = 144

Add remainder 7 to the L.C.M = 144+7= 151

The least number which when divided by 12,16,24 and 36 leaves a remainder 7 in each case IS 151

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