Question

Find the least number of 4 digits which is e axactly divisible by 14 ,21and28

Answer 1

The answer is 1008

1008/14 = 72

1008/21 = 48

1008/28 = 36

Answer 2

Hii...
Here is your answer..

Solution: -
Smallest 4 digit number=1000
LCM of 14,21 and 28=
$= > 2 \times 2 \times 3 \times 7 \\ = > 84$
when we divide 1000 by 84:-
$= > \frac{1000}{84} \\ = > 11.90$
And 11.90 is nearly 12.

So,
The smallest 4 digit number which is exactly divisible by 14,21 and 28 is:-
$= > 12 \times 84 \\ = > 1008$
Hence,the required number is 1008.

Hope it helps uh...✌️✌️✌️