Find the least number of 4 digits which keeps the remainder 1 after being divided by 15,18and 24.
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it is your answer
Step-by-step explanation:
LCM of 5, 10, 12, 15, 18, 25 and 30 is 900
Least 5 digit number 10000 Divide 10000 by 900. Remainder 100
Therefore, least 5 digit number exactly divisible by given divisors 10000 + (900 -100) =10800. Hence, required number = 10800 + 2 = 10802
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