find the least number of 4 digits which on dividing by 12,16,20 and 25 leaves remainder 8 in each case
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maalum nhi dekhle miljaye toh acha
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Step-by-step explanation:
Required Number
= L.C.M (12,16,20,25) + remainder
12 = 2×2×3 ,16 = 2×2×2×2
20 = 2×2×5 ,25 = 5×5
L.C.M = 2^4 × 5^2 × 3 = 1200
required least number
= 1200 +8 = 1208 Answer
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