Question

find the least number of 4digits which when divided by 6,8 and 12 leaves a remainder 3 in each case


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Answer 1

Answer:

3,6,8,12

this is the ans

hope help ful to u

Answer 2

Answer:

First take LCM of 4,6,10&15

We got 60

Now find multiple of 60 in 6 digit

We know least 6 digit number is 100,000

Now 100,000 by 60

100,000/60=1666.66667

If we round off quotient we got 1667

Now multiply 1667 by 60 then we get 100,020

100,020 divisible by 4,6,10 and 15

Now required number will be

100,020+2=100,022 Answer

Hope it helps