Find the least number of 5 digit exactly divisible bye 16,18,24,and 36
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Answered by
10
LCM of these numbers is divisible by all of these numbers
16 = 2*2*2*2
18 = 2*3*3
24 = 2*2*2*3
36 = 2*2*3*3
So, LCM = 2⁴*3² = 144
Lowest 5 digit number = 10,000
10,000/144 = 69.44
So, the least number of 5 digit exactly divisible bye 16,18,24,and 36
= 144*70
=10,080
#Prashant24IITBHU
16 = 2*2*2*2
18 = 2*3*3
24 = 2*2*2*3
36 = 2*2*3*3
So, LCM = 2⁴*3² = 144
Lowest 5 digit number = 10,000
10,000/144 = 69.44
So, the least number of 5 digit exactly divisible bye 16,18,24,and 36
= 144*70
=10,080
#Prashant24IITBHU
RehanAhmadXLX:
:-)
Answered by
6
Hey mate!
Here's your answer!!
The LCM of 16, 18, 24 and 36
= 2 × 2 × 2 × 2 × 3 × 3
= 144
We know that smallest 5 digit number = 10,000
10000/144 = 69.44 = 70
70 × 144 = 10,080
So, the required number is 10,080.
✌ ✌ ✌
#BE BRAINLY
Here's your answer!!
The LCM of 16, 18, 24 and 36
= 2 × 2 × 2 × 2 × 3 × 3
= 144
We know that smallest 5 digit number = 10,000
10000/144 = 69.44 = 70
70 × 144 = 10,080
So, the required number is 10,080.
✌ ✌ ✌
#BE BRAINLY
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