Math, asked by KunalSinha52, 9 months ago

find the least number of 5 digit which is exacy divisible by 10,15,20 and 25.​

Answers

Answered by lilykharnaiorlily
0

Answer:

the least number 5 digit is 1

Answered by Sheg
2

Answer:

10,200

Step-by-step explanation:

Take the LCM of 10,15,20 and 25. we get

5 × 2 × 3 × 2 × 5 = 300

Divide 10,000 by 300

we get 33.33333

This means the smallest 5 digit number that is exactly divided by 10, 15, 20 and 25 will be a multiple of 300.

Number = 34 × 300 = 10,200

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