Question

Find the least number of 5 digits that is exactly divisible by 32, 36 and 45

Answer 1

Hey

Here is your answer,

LCM of 32,36 and 45 =1440
Smallest 5 - digit no. =10000
Divide 10000 by 1440
Remainder = 1360
Req. no.=10000+(1440-1360)
             =10000+80
             =10080
Ans.=10800 is the smallest 5- digit no. exactly divisible by 32,36 and 45.

Hope it helps you!

Answer 2

Hey mate,

Here is ur answer,

We have to find the LCM of 32, 36 , 45.

LCM => 1440.

The least 5- digit number => 10000.

Divide the 10000 by 1440.

Remainder => 1360.

So, The number => 10,000-1360+1440.

=> 10,080.


:-)Hope it helps u. 《《 VIDYA 》》.