Question

find the least number of 5 digits which is exactly divisible by 10, 15, 20 and 25.​

Answer 1

Answer:

Step-by-step explanation:

To find the least 5 digit number which is exactly divisible by 20, 25 and 30, we have to find the LCM of 20, 25 and 30

20 = 2*2*5

25 = 5*5

30 = 2*3*5

LCM = 2*2*3*5*5

= 300

So, LCM of 20, 25 and 30 is 300. But we need the least 5 digit number, which is exactly divisible by 20, 25 and 30.  

Least 5 digit number = 10000.

10000 = (33*300) + 100

Next higher quotient is 34.

So, the required number = 34*300  

= 10200

Hence, the required number is 10200, which is exactly divisible by 20, 35 and 30

Answer.  

Answer 2

Answer:

The least number of 5 digits which is exactly divisible by $10, 15, 20 and 25.$ is 10200.

Step-by-step explanation:

According to the question , we need to find the least number of $5$ digits which is exactly divisible by $10, 15, 20 and 25.$

Firstly we need to find out the LCM of the four numbers is $300$.

Least number of $5$ digits is $10000$.

If we divide $10000$ by $300$ then the quotient is $33$.

So the number is $300(33+1)=10200$.

The least number of 5 digits which is exactly divisible by $10, 15, 20 and 25.$ is 10200.

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