Question

find the least number of 5-digits which leaves remainder 2 in each case when divided by 6,8 and 45​

Answer 1

Answer:

Step-by-step explanation:

Least 5 digit number  = 10000.

LCM(4,12,20,24) = 120

Dividing 10000 by 120 leaves a remainder 40 , Subtract 40 from 10000 = 9960

So this means 9960 is divisible by 120.

9960 + 120 = 10080.

To find the number which leaves remainder 3, we have to add 3 to 10080.

10080 + 3 = 10083.

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Suhaniyadav05Ambitious

Answer: Least 5 digit number  = 10000.

LCM(4,12,20,24) = 120

Dividing 10000 by 120 leaves a remainder 40 , Subtract 40 from 10000 = 9960

So this means 9960 is divisible by 120.

9960 + 120 = 10080.

To find the number which leaves remainder 3, we have to add 3 to 10080.

10080 + 3 = 10083.

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