Math, asked by shweta33, 1 year ago

Find the least number of 5 digits which on dividing by 12, 16, 20 and 25 leaves remainder 8 in each case

Answers

Answered by Anonymous
50
let's find LCM (12,16,20,25)
12=2²×3
16=2⁴
20=2²×5
25=5²
LCM=2⁴×3×5²=1200
we know that least five digit number is 10000
dividing 10000 by 1200 we get 400 as remainder and quotient as 8.333(approx)
now , 1200×8 +8 but we r getting a four digit number so

required number =1200×9+8=10808

Anonymous: hope this helped u
Anonymous: comment here if u have doubts
Answered by 25Vaibhav147
8
hey mate hope it will help you

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