Question

find the least number of 5 digits which on dividing by 3,12,18,24,30 leaves remainder 8 in each case​

Answer 1

Answer:

The LCM of 3,12,18,24,30,36 is 360

We have the greatest five digit number : 99999

When 99999 is divided by 360, leaves the remainder 279

So, 99999−279=99720

Now here, we can see that

3−2=1, 12−11=1, 18−17=1, 24−23=1, 30−29=1, 36−35=1

The difference of divisors and their corresponding remainders is 1.

So, the required five digit number will be 1 less than $99720$$.

The required number is 99720−1=99719

Step-by-step explanation: