Question

find the least number of 5 digits which on divinting by 12, 16, 20,and 25 leaves remainder 8 in each case

Answer 1

Least 5 digit number  = 10000.

LCM(4,12,20,24) = 120

Dividing 10000 by 120 leaves a remainder 40 , Subtract 40 from 10000 = 9960



So this means 9960 is divisible by 120.



9960 + 120 = 10080.



To find the number which leaves remainder 3, we have to add 3 to 10080.



10080 + 3 = 10083.



Hope this helps!

Answer 2

hey mate hope it will help you