Find the least number of 6 digit from which if 26 is subtracted, the resultant number is exactly divisible by 16, 20, 24, and 36
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Answered by
7
Answer:
Here is ur answer
Step-by-step explanation:
First calculate the LCM of 16,24 and 36:
The LCM of 16,24 and 36 is 144
Now,144 is the least number which is exactly divided by 16,24 and 36
Next, Add 26:
144+26=170.
So 170 is the least number from which 26 is Subtracted,the result is exactly divisible by 16,24 and 36.
Verification:
170-26=144
144/24=6
144/16=9
144/36=4
the reminder is zero in each case
Answered by
1
L. C. M for 16,24 and 36 and varification 170-26=144
144/24=6
144/16=9
144/36=4
The reminder is zero in each case.
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