Find the least number of 6 digit which is a perfect square find the square root of this number
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Answered by
4
Answer:
317²
Explanation:
The smallest number of 6 digits=100000=10^5
Now the square root of 10^5:
√10^5=100√10=316.23 (As √10=3.1623)**
Now, to be the smallest number of six digits, the number must be greater than (316.23^2) and it's swuare root must be an integer.
Now the nearest integer to 316.23 that is greter than itself is, 317.
So, the smallest 6 digit perfect square will be:
317^2=100489
Answered by
3
Answer:
your ans is
Explanation:
your answer is 100489
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