Question

find the least number of five digit which is exactely divisible by 32, 36 and 45.​

Answer 1

Answer:

10080

Step-by-step explanation:

First take out the LCM of 32,36 and 45.

LCM=1440

Smallest 5 digit number=10000

Divide 10000 by 1440

Remainder is 1360

Req. no.=10000+(1440-1360)

             =10000+80

             =10080

10080 is the least no. of 5 digits which is exactly divisible by 32,36 and 45.