find the least number of five digit which is exactly divisible by 32,36,45
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Answer:
The LCM of 32, 36 , 40 and 45 is 360.
The smallest 5 digit number =10000
(Divide 10000 by 360)
The remeinder is 280.
Required number=10000-(divisor- remainder)
=10000+(360- 280)
= 10000+ 80
= 10080
Therefore the least number which is exactly divisible by 32,36 and 45 is 10080.
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