Find the least number of five digits exactly divisible by 12,15,18,24
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Answer:
Let us divide it by 180. We get a quotient 55 remainder is 100. If we add 80 to it then it will be completely divided by 180 with a quotient 56. So, smallest 5-digits number divisible by 12, 15, and 18 is 10080.
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Step-by-step explanation:
Let us divide it by 180. We get a quotient 55 remainder is 100. If we add 80 to it then it will be completely divided by 180 with a quotient 56. So, smallest 5-digits number divisible by 12, 15, and 18 is 10080.
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