find the least number of five digits, which is exactly divisible by 36.
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Step-by-step explanation:
First we have to find the LCM of 8,20 and 24
∴ LCM of given numbers =2×2××2×3×5=120
Greatest number of 3 digit is 999
We divide 999 by 120 and find the remainder
According to given condition , we need a greatest 3-digit number which is exactly divisible by 120
∴ The required number =999−39=960
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