Question

Find the least number of five digits which on being divided by 72, 144, 192 l
eaves the remainders 67, 139, 187 respectively.​

Answer 1

Answer:

Step-by-step explanation:first we have to find LCM of 72,144 and 192

LCM=576

As we know least 5 digit no =10000

Dividing 10000 by LCM i.e 576

10000/576 leaves the remainder 208

Subtract 208 from 10000 so it will become perfect divisible

i.e, 10000-208=9792

But we have to show least 5 digit no, so we will add 576 to 9792

9792+576=10368

Now 72-67=5

144-139=5

192-187=5

Now subtract this 5 from10368

10368-5=10363

Hence 10363 is the required five digit no which on being divided by 72,144 and 192 leaves the remainders 67,139 and 187 respectively