Math, asked by aaravthemaster2, 1 year ago

Find the least number of five digits which on dividing by 15, 20, 25, 30 and 35 leaves a remainder
7 in each case.

Answers

Answered by streetburner

2

Answer:

10507

Step-by-step explanation:

The simplest method is :

Find LCM & and 7 !

LCM f 15,20,25,30 & 35 is :

5 digit number should be

(2100×5)+7 = 10507

Answered by mallikasingh0

2

Answer:

hope it helps you

please mark me as brainliest

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