Question

Find the least number of five digits which when divided by 8,12, 28, 36 and 40 leaves a
remainder 6 in each case.​

Answer 1

Answer:

take lcm of 8 12 28 36 40 .

Step-by-step explanation:

8 = 2^3

12 = 2^2 * 3

28 = 2^2 * 7

36 = 2^2 * 3^2

40 = 2^3 * 5

lcm = 2 * 2 * 2 * 3 * 3 * 5 * 7 = 2520

but we know that smallest 5 digit no. is 10000

10000/2520 = 3 ( approx ) and leaves remainder = 2440

required number = 10000 + ( 2520 - 2440 ) + 6

= 10000 + 86

= 10086.