Find the least number of four digits which is exactly divisible by 24 30 32 and 36
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The number that I came up with was 9,072. I found the LCM (Least Common Multiple) using Prime factorization which was 1,008 but you wanted the highest 4 digit number so I multiplied 1,008 to the highest whole number that would still render a 4 digit answer, which was 9 (1,008 * 9 = 9,072).
12 = 2 x 2 x 3
16 = 2 x 2 x 2 x 2
24= 2 x 2 x 2 x 3
28 = 2 x 2 x 7
36 = 2 x 2 x 3 x 3
LCM = 2 x 2 x 2 x 2 x 3 x 3 x 7 = 1,008
1,008 x 9 = 9,072
9,072 is divisible by 12(756), 16 (567), 24 (378), 28 (324), & 36(252)
12 = 2 x 2 x 3
16 = 2 x 2 x 2 x 2
24= 2 x 2 x 2 x 3
28 = 2 x 2 x 7
36 = 2 x 2 x 3 x 3
LCM = 2 x 2 x 2 x 2 x 3 x 3 x 7 = 1,008
1,008 x 9 = 9,072
9,072 is divisible by 12(756), 16 (567), 24 (378), 28 (324), & 36(252)
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