Math, asked by 88kumarkrnitin, 1 day ago

Find the least number of four digits which when divided by 2. 3, 4,5 and 6 leaves in each case a remainder 1

Answers

Answered by amanraj56

0

Step-by-step explanation:

LCM of 2,3,4,5and6 = 60

smallest 4digit no. divisible by 60 = 1020

smallest 4digit no. leaves remainder

as 1 when divisible by 2,3,4,5and6 = (1020+1)

= 1021

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