Find the least number of four digits which when divided by 24, 16 and 12 leaves a remainder of 5 in each case.
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Answered by
1
Answer:
least number of 4 digit is 1000
LCM of 24,16,12 is 48
on dividing 1000÷48 the remainder is 40.
so 1000+(48-40)=1008
remainder is 5 so the number is 1008+5=1013
Hope it helps✌️
Answered by
1
Answer:
24, 16 ও 12 এর লসাগু = 48
চার অঙ্কের ক্ষুদ্রতম সংখ্যা 1000
1000÷48
48|1000|2
96
______
40
উত্তর 1000+8=1008
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