Math, asked by archanadeshpandenvr, 10 months ago

Find the least number of six digit that is a perfect square.​

Answers

Answered by kumail15
0

Step-by-step explanation:

Let x² be the largest six-digit perfect square. x² ≤ 999,999. You know that 1,000² = 1,000,000, which is only 1 more than 999,999, so x² must be the next smaller square, which is (1,000 - 1)². (1,000 - 1)² = 999² = 998,001.

Answered by nm097690
0

Answer:

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