Find the least number of six digit that is a perfect square.
Answers
Answered by
0
Step-by-step explanation:
Let x² be the largest six-digit perfect square. x² ≤ 999,999. You know that 1,000² = 1,000,000, which is only 1 more than 999,999, so x² must be the next smaller square, which is (1,000 - 1)². (1,000 - 1)² = 999² = 998,001.
Answered by
0
Answer:
please mark me as brainlist
Attachments:
Similar questions